Consider compounds A,B,and C with the followi | vedclass

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(D) The conversion of alcohol $A$ $(pentan-1-ol)$ to alkene $B$ $(pent-1-ene)$ is a dehydration reaction.
Dehydration of alcohols is typically carrie

Vedclass · Accepted Answer

$D$: conc. $H_2SO_4$ or $H_3PO_4$,$E$: $CH_2 = CH - CH = CH_2$

Vedclass · Answer

(D) The conversion of alcohol $A$ $(pentan-1-ol)$ to alkene $B$ $(pent-1-ene)$ is a dehydration reaction.
Dehydration of alcohols is typically carried out using a strong acid catalyst like concentrated $H_2SO_4$ or $H_3PO_4$ at high temperatures.
Compound $C$ is $butane-1,3-diol$ $(HO-CH_2-CH_2-CH(OH)-CH_3)$.
When $C$ reacts with an excess of a dehydrating agent like concentrated $H_2SO_4$,both hydroxyl $(-OH)$ groups are removed to form two double bonds,resulting in the formation of a diene.
The product $E$ is $buta-1,3-diene$ $(CH_2=CH-CH=CH_2)$.

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