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(D) When a charge $\Delta q$ moves through a potential difference $V$,the change in its electric potential energy is given by $\Delta U = \Delta q \cd

Vedclass · Accepted Answer

$II$ and $III$

Vedclass · Answer

(D) When a charge $\Delta q$ moves through a potential difference $V$,the change in its electric potential energy is given by $\Delta U = \Delta q \cdot V$. Since $I = \frac{\Delta q}{\Delta t}$,we have $\Delta q = I \Delta t$. Thus,the potential energy decreases by $I V \Delta t$.In a steady current,the drift velocity of the charge carriers remains constant,meaning the kinetic energy of the charge does not increase significantly. Instead,the lost potential energy is dissipated as heat due to collisions with the lattice ions of the conductor.Therefore,the thermal energy of the conductor increases by $I V \Delta t$.Statements $II$ and $III$ are correct.

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