Consider a glass prism immersed in a liquid a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The given situation is shown in the figure. The light ray enters the prism perpendicular to the face $AB$,so it passes undeviated into the prism a

Vedclass · Accepted Answer

$\cos ^{-1}(0.8)$

Vedclass · Answer

(A) The given situation is shown in the figure. The light ray enters the prism perpendicular to the face $AB$,so it passes undeviated into the prism and strikes the face $AC$.In the triangle formed by the prism,the angle of incidence $i$ at the face $AC$ is $i = 90^{\circ} - 	heta$.For total internal reflection to occur at face $AC$,the angle of incidence $i$ must be greater than or equal to the critical angle $i_c$.Thus,for the largest value of $	heta$,we set $i = i_c$.Using Snell's law at the interface $AC$ for the critical angle condition:$\sin(i_c) = \frac{\mu_{	ext{liquid}}}{\mu_{	ext{glass}}}$Substituting $i = 90^{\circ} - 	heta$ and the given refractive indices:$\sin(90^{\circ} - 	heta) = \frac{1.2}{1.5}$$\cos(	heta) = \frac{12}{15} = \frac{4}{5} = 0.8$Therefore,$	heta = \cos^{-1}(0.8)$.

Similar Questions

$A$ point source of light is placed $4 \; m$ below the surface of water of refractive index $5/3$. The minimum diameter of a disc which should be placed over the source on the surface of water to cut-off all light coming out of water is ... $m$.

$A$ transparent solid cylindrical rod has a refractive index of $\frac{2}{\sqrt{3}}$. It is surrounded by air. $A$ light ray is incident at the mid-point of one end of the rod as shown in the figure. The incident angle $\theta$ for which the light ray grazes along the wall of the rod is

Light travels in two media $A$ and $B$ with speeds $1.8 \times 10^8 \ m/s$ and $2.4 \times 10^8 \ m/s$ respectively. Then the critical angle between them is

'Mirage' is a phenomenon due to

Vedclass Test Series

Exam Paper Generator

Online Exam Module