Consider the following reactions:NaCl + K_{2} | vedclass

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(C) The reactions are as follows:$4 NaCl + K_{2}Cr_{2}O_{7} + 6 H_{2}SO_{4} \rightarrow 2 CrO_{2}Cl_{2} (A) + 4 NaHSO_{4} + 2 KHSO_{4} + 3 H_{2}O$$CrO

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$18$

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(C) The reactions are as follows:$4 NaCl + K_{2}Cr_{2}O_{7} + 6 H_{2}SO_{4} \rightarrow 2 CrO_{2}Cl_{2} (A) + 4 NaHSO_{4} + 2 KHSO_{4} + 3 H_{2}O$$CrO_{2}Cl_{2} (A) + 4 NaOH \rightarrow Na_{2}CrO_{4} (B) + 2 NaCl + 2 H_{2}O$$Na_{2}CrO_{4} (B) + 2 H_{2}SO_{4} + 2 H_{2}O_{2} \rightarrow CrO_{5} (C) + 2 NaHSO_{4} + 3 H_{2}O$Identifying the compounds:$(A) = CrO_{2}Cl_{2}$ (Chromyl chloride),number of atoms $= 1 + 2 + 2 = 5$$(B) = Na_{2}CrO_{4}$ (Sodium chromate),number of atoms $= 2 + 1 + 4 = 7$$(C) = CrO_{5}$ (Chromium pentoxide),number of atoms $= 1 + 5 = 6$Sum of total atoms $= 5 + 7 + 6 = 18$.

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