The concentration of $[CN^{-}]$ in $0.1 \, M \, HCN$ solution is: $(K_a = 4 \times 10^{-10})$
- A$2.5 \times 10^{-6} \, M$
- B$4.5 \times 10^{-6} \, M$
- C$6.3 \times 10^{-6} \, M$
- D$9.2 \times 10^{-6} \, M$
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