CompoundTotal stereoisomersA. [Co(en)_2Cl_2]^ | vedclass

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(B) . $[Co(en)_2Cl_2]^+$: This complex shows cis-trans isomerism. The cis-isomer is optically active ($2$ enantiomers) and the trans-isomer is optical

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$A-Q, B-P, C-P, D-P$

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(B) . $[Co(en)_2Cl_2]^+$: This complex shows cis-trans isomerism. The cis-isomer is optically active ($2$ enantiomers) and the trans-isomer is optically inactive. Total stereoisomers = $2 + 1 = 3$ $(Q)$.$B$. $[Co(en)_3]Cl_3$: This complex has $2$ optical isomers (enantiomers) and no geometric isomers. Total stereoisomers = $2$ $(P)$.$C$. $[Pt(NH_3)_2Cl_2]$: This is a square planar complex showing cis-trans isomerism. Both are optically inactive. Total stereoisomers = $2$ $(P)$.$D$. $[Pt(NH_3)_3Cl_3]^+$: This is an octahedral complex showing facial (fac) and meridional (mer) isomers. Both are optically inactive. Total stereoisomers = $2$ $(P)$.Therefore,the correct matching is $A-Q, B-P, C-P, D-P$.

Compound Total stereoisomers
$A$. $[Co(en)_2Cl_2]^+$ $P$. $2$
$B$. $[Co(en)_3]Cl_3$ $Q$. $3$
$C$. $[Pt(NH_3)_2Cl_2]$ $R$. $4$
$D$. $[Pt(NH_3)_3Cl_3]^+$ $S$. $5$

Match the compounds with their total number of stereoisomers and select the correct code:

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Compound	Total stereoisomers
$A$. $[Co(en)_2Cl_2]^+$	$P$. $2$
$B$. $[Co(en)_3]Cl_3$	$Q$. $3$
$C$. $[Pt(NH_3)_2Cl_2]$	$R$. $4$
$D$. $[Pt(NH_3)_3Cl_3]^+$	$S$. $5$

CompoundTotal stereoisomers$A$. $[Co(en)_2Cl_2]^+$$P$. $2$$B$. $[Co(en)_3]Cl_3$$Q$. $3$$C$. $[Pt(NH_3)_2Cl_2]$$R$. $4$$D$. $[Pt(NH_3)_3Cl_3]^+$$S$. $5$Match the compounds with their total number of stereoisomers and select the correct code: