Complete the following chemical equations:
$4BF_{3} + 3LiAlH_{4} \to 2B_{2}H_{6} (X) + 3LiF + 3AlF_{3}$
$B_{2}H_{6} (X) + 6H_{2}O \to 2H_{3}BO_{3} (Y) + 6H_{2}$
$B_{2}H_{6} (X) + 3O_{2} \xrightarrow{\Delta} B_{2}O_{3} + 3H_{2}O$

The given reactions represent the synthesis and chemical properties of diborane $(B_{2}H_{6})$.
$(i)$ The reaction of boron trifluoride with lithium aluminium hydride produces diborane: $4BF_{3} + 3LiAlH_{4} \to 2B_{2}H_{6} (X) + 3LiF + 3AlF_{3}$.
$(ii)$ Diborane reacts with water to form orthoboric acid: $B_{2}H_{6} + 6H_{2}O \to 2H_{3}BO_{3} (Y) + 6H_{2}$.
$(iii)$ Diborane undergoes combustion in oxygen to form boron trioxide and water: $B_{2}H_{6} + 3O_{2} \xrightarrow{\Delta} B_{2}O_{3} + 3H_{2}O$.
Therefore,$X = B_{2}H_{6}$ and $Y = H_{3}BO_{3}$.