Complete reduction of $benzene-diazonium$ chloride with $Zn/HCl$ gives:

  • A
    Aniline
  • B
    Phenylhydrazine
  • C
    Azobenzene
  • D
    Hydrazobenzene

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The major product of the reaction is:

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$(i)$ Carbylamine reaction
$(ii)$ Diazotisation
$(iii)$ Hofmann's bromamide reaction
$(iv)$ Coupling reaction
$(v)$ Ammonolysis
$(vi)$ Acetylation
$(vii)$ Gabriel phthalimide synthesis.

The reaction of $p$-toluidine with chloroform and alcoholic $KOH$ forms:

In the series of reactions: $C_6H_5NH_2$ $\xrightarrow{NaNO_2/HCl}_{0 - 5\ ^\circ C} X$ $\xrightarrow{HNO_2}_{H_2O} Y + N_2 + HCl$. $X$ and $Y$ are respectively:

Given below are two statements: one is labelled as Assertion $(A)$ and the other is labelled as Reason $(R)$.
Assertion $(A)$: Experimental reaction of $CH_{3}Cl$ with aniline and anhydrous $AlCl_{3}$ does not give $o-$ and $p-$methylaniline.
Reason $(R)$: The $-NH_{2}$ group of aniline becomes deactivating because of salt formation with anhydrous $AlCl_{3}$ and hence yields $m-$methylaniline as the product.
In the light of the above statements,choose the most appropriate answer from the options given below.

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