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(D) The stability of resonating structures is determined by the following rules:$1$. Structures with more covalent bonds are more stable.$2$. Structur

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$p > r > q$

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(D) The stability of resonating structures is determined by the following rules:$1$. Structures with more covalent bonds are more stable.$2$. Structures with negative charge on a more electronegative atom are more stable.$3$. Structures with less charge separation are more stable.Analyzing the structures:- Structure $(p)$ has a negative charge on the oxygen atom,which is highly electronegative,making it very stable.- Structure $(q)$ has a negative charge on a carbon atom,which is less electronegative than oxygen,making it less stable than $(p)$.- Structure $(r)$ is a neutral molecule with no charge separation,but it contains a $C=C=N$ system which is less stable than the $C \equiv N$ system found in $(p)$ and $(q)$ due to the accumulation of double bonds on the carbon atom.Comparing $(p)$ and $(q)$,$(p)$ is more stable because the negative charge is on the oxygen atom.Comparing $(p)$ and $(r)$,$(p)$ is more stable due to the octet completion on all atoms.Comparing $(r)$ and $(q)$,$(r)$ is more stable than $(q)$ because $(q)$ has a formal negative charge on carbon.Therefore,the stability order is $p > r > q$.

Compare the relative stability of the following resonating structures:

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