Compare the x and y bond angles for the given | vedclass

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(B) In the given molecules,$x$ is the $O=S=O$ bond angle in $SO_2F_4$ (or similar structure) and $y$ is the $O=I-F$ bond angle in $IOF_4^-$. According

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$x > y$

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(B) In the given molecules,$x$ is the $O=S=O$ bond angle in $SO_2F_4$ (or similar structure) and $y$ is the $O=I-F$ bond angle in $IOF_4^-$. According to $VSEPR$ theory,multiple bonds exert greater repulsion than single bonds. However,the bond angle is also influenced by the electronegativity of the central atom and the surrounding atoms. In $SO_2F_4$,the $S=O$ double bonds exert more repulsion than the $S-F$ single bonds,pushing the $F-S-F$ or $O-S-O$ angles. Comparing the structures,the repulsion from the double bond in the sulfur compound is significant,but due to the larger size of the Iodine atom and the specific geometry of the $IOF_4^-$ ion,the bond angle $x$ is found to be greater than $y$ $(x > y)$.

List-$I$ (molecule/ion)	List-$II$ (Number of lone pairs of electrons on the central atom)
$(A)$ $XeF_2$	$(I)$ $2$
$(B)$ $XeO_3$	$(II)$ $0$
$(C)$ $XeF_4$	$(III)$ $3$
$(D)$ $PF_6^-$	$(IV)$ $1$

Compare the $x$ and $y$ bond angles for the given molecules.

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