Coagulating value of electrolytes AlCl_3 and | vedclass

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(A) The coagulating power of an electrolyte is inversely proportional to its coagulating value.$	ext{Coagulating Power} (C.P.) = \frac{1}{	ext{Coagu

Vedclass · Accepted Answer

$556$

Vedclass · Answer

(A) The coagulating power of an electrolyte is inversely proportional to its coagulating value.$	ext{Coagulating Power} (C.P.) = \frac{1}{	ext{Coagulating Value} (C.V.)}$Given:$(C.V.)_{AlCl_3} = 0.09$$(C.V.)_{NaCl} = 50.04$Ratio of coagulating powers:$\frac{(C.P.)_{AlCl_3}}{(C.P.)_{NaCl}} = \frac{(C.V.)_{NaCl}}{(C.V.)_{AlCl_3}}$$\frac{(C.P.)_{AlCl_3}}{(C.P.)_{NaCl}} = \frac{50.04}{0.09} = 556$Therefore,the coagulating power of $AlCl_3$ is $556$ times the coagulating power of $NaCl$. Thus,$x = 556$.

Coagulating value of electrolytes $AlCl_3$ and $NaCl$ for $As_2S_3$ are $0.09$ and $50.04$ respectively. The coagulating power of $AlCl_3$ is $x$ times the coagulating power of $NaCl$. The value of $x$ is $.......$.

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