Coordination number of $Fe$ in the complexes $[Fe(CN)_6]^{4-}$,$[Fe(CN)_6]^{3-}$ and $[FeCl_4]^{-}$ would be respectively

  • A
    $2, 3, 3$
  • B
    $6, 6, 4$
  • C
    $6, 3, 3$
  • D
    $6, 4, 6$

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One mole of the octahedral complex compound $Co(NH_3)_5Cl_3$ gives $3$ moles of ions on dissolution in water. One mole of the same complex reacts with excess of $AgNO_3$ solution to yield two moles of $AgCl_{(s)}$. The structure of the complex is :

Turnbull's blue is

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