Citric acid is formed in the Krebs cycle by t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In the Krebs cycle, the first step is the condensation reaction where the $2$-carbon compound Acetyl $CoA$ combines with the $4$-carbon compound O

Vedclass · Accepted Answer

Acetyl $CoA$

Vedclass · Answer

(B) In the Krebs cycle, the first step is the condensation reaction where the $2$-carbon compound Acetyl $CoA$ combines with the $4$-carbon compound Oxaloacetate $(OAA)$ in the presence of water and the enzyme Citrate synthase to form a $6$-carbon compound called Citric acid (Citrate).Reaction: $OAA + 	ext{Acetyl } CoA + H_2O \xrightarrow{	ext{Citrate synthase}} 	ext{Citric acid} + CoA + H^+$

Citric acid is formed in the Krebs cycle by the combination of oxaloacetate with:

Similar Questions

Acetyl $Co-A$ binds to oxaloacetic acid to form

The mineral activator required for the carboxylase enzymes of the $TCA$ cycle is

Pyruvate (pyruvic acid) dehydrogenase is used in converting

How many $NADH$ and $FADH_2$ are formed when one molecule of citric acid enters the $TCA$ cycle?

Assertion: In Krebs cycle,there is a one step where substrate level phosphorylation occurs.
Reason: During the formation of succinyl $\text{CoA}$ to succinic acid,a molecule of $\text{GTP}$ is synthesized.

Vedclass Test Series

Exam Paper Generator

Online Exam Module