Citrate,the first stable product of the Krebs | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In the Krebs cycle (Tricarboxylic Acid Cycle),$1$ molecule of citrate $(6C)$ is converted back to oxaloacetate $(4C)$.During this process,the foll

Vedclass · Accepted Answer

Four and two

Vedclass · Answer

(A) In the Krebs cycle (Tricarboxylic Acid Cycle),$1$ molecule of citrate $(6C)$ is converted back to oxaloacetate $(4C)$.During this process,the following steps occur:$1$. Decarboxylation: Two molecules of $CO_2$ are released. One during the conversion of isocitrate to $\alpha$-ketoglutarate,and another during the conversion of $\alpha$-ketoglutarate to succinyl-CoA.$2$. Oxidation: Four oxidation steps occur where $NAD^+$ or $FAD$ are reduced to $NADH$ or $FADH_2$. These are: $(i)$ Isocitrate to $\alpha$-ketoglutarate,(ii) $\alpha$-ketoglutarate to succinyl-CoA,(iii) Succinate to fumarate,and (iv) Malate to oxaloacetate.Therefore,there are $4$ oxidation steps and $2$ decarboxylation steps.

Citrate,the first stable product of the Krebs cycle,undergoes how many oxidation and decarboxylation steps respectively to regenerate oxaloacetate?

Similar Questions

In respiration,pyruvic acid is .........

During the citric acid cycle,various organic acids undergo decarboxylation. Which of the following organic acids of the cycle have $4C$,$5C$,and $6C$ respectively?

The acetyl group of acetyl CoA contains how many carbon atoms?

Which of the following is not a part of the $Kreb's$ cycle?

How many $ATP$ molecules are produced during the oxidation of succinate to fumarate (in $ATP$)?

Vedclass Test Series

Exam Paper Generator

Online Exam Module