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(B) To determine the electronic configuration of ions,we look at the number of electrons after ionization:$1$. $Li^+$ ion: $Li$ $(Z=3)$ has $3$ electr

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Potassium and calcium

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(B) To determine the electronic configuration of ions,we look at the number of electrons after ionization:$1$. $Li^+$ ion: $Li$ $(Z=3)$ has $3$ electrons. $Li^+$ has $3-1 = 2$ electrons. Configuration: $1s^2$ (similar to $He$).$2$. $Na^+$ ion: $Na$ $(Z=11)$ has $11$ electrons. $Na^+$ has $11-1 = 10$ electrons. Configuration: $1s^2 2s^2 2p^6$ (similar to $Ne$).$3$. $K^+$ ion: $K$ $(Z=19)$ has $19$ electrons. $K^+$ has $19-1 = 18$ electrons. Configuration: $1s^2 2s^2 2p^6 3s^2 3p^6$ (similar to $Ar$).$4$. $Ca^{2+}$ ion: $Ca$ $(Z=20)$ has $20$ electrons. $Ca^{2+}$ has $20-2 = 18$ electrons. Configuration: $1s^2 2s^2 2p^6 3s^2 3p^6$ (similar to $Ar$).Comparing the ions,$K^+$ and $Ca^{2+}$ both have $18$ electrons and the same electronic configuration.

Choose the pair whose ions have the similar electronic configuration.

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