Choose the correct statement regarding the formation of carbocations $A$ and $B$ given:
$CH_3-CH_2-CH=CH_2 + HBr \to CH_3-CH_2-CH_2-CH_2^+ + Br^-$ $(A)$
$CH_3-CH_2-CH=CH_2 + HBr \to CH_3-CH_2-CH^+-CH_3 + Br^-$ $(B)$

  • A
    Carbocation $B$ is more stable and formed relatively at a faster rate.
  • B
    Carbocation $A$ is more stable and formed relatively at a slow rate.
  • C
    Carbocation $B$ is more stable and formed relatively at a slow rate.
  • D
    Carbocation $A$ is more stable and formed relatively at a faster rate.

Explore More

Similar Questions

Which of the following is the most stable free radical?

Difficult
View Solution

Which of the following carbocations is the most stable?

State whether the following statements are True or False:
$(i)$ $CH_3-CH_2^+$ is more stable than $CH_3^+$
$(ii)$ $CH_3-CH_2^+$ is less stable than $CH_3^+$
$(iii)$ $(CH_3)_3C^+$ is less stable than $CH_3^+$
$(iv)$ $(CH_3)_3C^+$ is more stable than $CH_3^+$

Classify the following species into carbocation,free radical,and carbanion:
$CH_3^{\bullet}, CH_3^{+}, \bar{C}H_3, (CH_3)_3C^{\bullet}, (CH_3)_3C^{+}, (CH_3)_2CH^{+}, (CH_3)_3\bar{C}:, (CH_3)_3\ddot{C}H, C_6H_5CH_2^{\bullet}, CH_3\ddot{C}H_2, C_6H_5CH_2^{+}, CH_2=CHCH_2^{\bullet}, CH_2=CHCH_2^{+}$

Find out the number of $1-2-$shifts during the conversion of the given carbocation to the final alkene product.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo