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(B) $1$. First,the $trans$-alkene reacts with $Br_2$ to form a vicinal dibromide: $Ph-CH(Br)-CH(Br)-CH_3$.$2$. Next,dehydrohalogenation occurs using $

Vedclass · Accepted Answer

$Br_2, 	ext{alc. } KOH, NaNH_2, H_2, 	ext{Lindlar Catalyst}$

Vedclass · Answer

(B) $1$. First,the $trans$-alkene reacts with $Br_2$ to form a vicinal dibromide: $Ph-CH(Br)-CH(Br)-CH_3$.$2$. Next,dehydrohalogenation occurs using $alc. KOH$ followed by $NaNH_2$ to remove two moles of $HBr$,resulting in the formation of an alkyne: $Ph-C \equiv C-CH_3$.$3$. Finally,the partial hydrogenation of the alkyne to a $cis$-alkene is achieved using $H_2$ with $Lindlar 	ext{ } Catalyst$ (a poisoned $Pd$ catalyst).$4$. Therefore,the correct sequence is $Br_2, 	ext{alc. } KOH, NaNH_2, H_2, 	ext{Lindlar Catalyst}$.

Choose the correct set of reagents for the following conversion:
$trans-(Ph-CH=CH-CH_3) \rightarrow cis-(Ph-CH=CH-CH_3)$

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Choose the correct set of reagents for the following conversion:$trans-(Ph-CH=CH-CH_3) \rightarrow cis-(Ph-CH=CH-CH_3)$