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(B) The reaction of an alkene with $Br_2$ in the presence of $H_2O$ is a halohydrin formation reaction.This reaction proceeds through the formation of

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$2-$bromo$-1-$ethylcyclohexan$-1-$ol

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(B) The reaction of an alkene with $Br_2$ in the presence of $H_2O$ is a halohydrin formation reaction.This reaction proceeds through the formation of a cyclic bromonium ion intermediate.Water acts as a nucleophile and attacks the more substituted carbon atom of the bromonium ion due to its higher partial positive charge.This results in an anti-addition of the $-Br$ and $-OH$ groups across the double bond.For the given substrate,$1$-ethylcyclohexene,the $-OH$ group will attach to the carbon bearing the ethyl group,and the $-Br$ atom will attach to the adjacent carbon,resulting in the formation of $2-$bromo$-1-$ethylcyclohexan$-1-$ol.

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