Choose the correct option for the following m | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The given molecule is $1,4-dichlorobuta-1,2,3-triene$.In cumulenes with an even number of double bonds,the terminal groups lie in perpendicular pl

Vedclass · Accepted Answer

both $(a)$ and $(b)$

Vedclass · Answer

(C) The given molecule is $1,4-dichlorobuta-1,2,3-triene$.In cumulenes with an even number of double bonds,the terminal groups lie in perpendicular planes.Since the molecule has three double bonds (an odd number of $\pi$ bonds between the terminal carbons),the terminal $CH-Cl$ groups lie in perpendicular planes.This makes the molecule non-planar.Due to the perpendicular arrangement of the terminal groups,the dipole moments of the two $C-Cl$ bonds do not cancel each other out,resulting in a non-zero net dipole moment $(\mu 
eq 0)$.Therefore,the molecule is non-planar and has a non-zero dipole moment.

Choose the correct option for the following molecule in view of chemical bonding:
$Cl-CH=C=C=CH-Cl$

Similar Questions

Which of the following compounds will show the highest dipole moment?

Which molecule is polar?

Arrange the following molecules from most to least polar ($I$,$II$,$III$,$IV$,$V$ respectively): $CH_4$,$CF_2Cl_2$,$CF_2H_2$,$CCl_4$,$CCl_2H_2$.

Which one of the following compounds has a non-zero dipole moment?

Identify the correct order of average molecular dipole moment for the following species: $PCl_3F_2$, $N_2O_{4(g)}$, and $N_2O_{4(s)}$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Choose the correct option for the following molecule in view of chemical bonding:$Cl-CH=C=C=CH-Cl$