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(A) $1$. The starting material $C_6H_{10}O$ is cyclohexanone. Reaction with $CH_3MgBr$ followed by $H_2O$ gives $1$-methylcyclohexanol $(Q)$.$2$. $Q$

Vedclass · Accepted Answer

$2,4$

Vedclass · Answer

(A) $1$. The starting material $C_6H_{10}O$ is cyclohexanone. Reaction with $CH_3MgBr$ followed by $H_2O$ gives $1$-methylcyclohexanol $(Q)$.$2$. $Q$ reacts with $conc. HCl$ to form $1$-chloro-$1$-methylcyclohexane $(S)$. This matches structure $(2)$.$3$. $Q$ undergoes acid-catalyzed dehydration with $20\% H_3PO_4$ at $360 \ K$ to form $1$-methylcyclohexene $(R)$.$4$. $R$ reacts with $HBr$ in the presence of benzoyl peroxide (anti-Markovnikov addition) to form $1$-bromo-$2$-methylcyclohexane $(U)$. This matches structure $(4)$.$5$. $R$ undergoes hydrogenation $(H_2, Ni)$ to form methylcyclohexane,followed by radical bromination $(Br_2, h
u)$ to form $1$-bromo-$1$-methylcyclohexane $(T)$.$6$. Comparing the structures: $S$ is $(2)$,$U$ is $(4)$,and $T$ is $(1)$. The correct set is $(2, 4)$.

Choose the correct option$(s)$ for the following set of reactions:

Similar Questions

Match the reactions given in Column-$I$ with the types of reactions given in Column-$II$.

In the following reaction sequence,
$Br-CH_2-CH(Br)-Ph$ $\xrightarrow[2. NaNH_2]{1. Alc. KOH} X$ $\xrightarrow[4. Conc. HNO_3/H_2SO_4]{3. HgSO_4/dil. H_2SO_4, Heat} Y$
$X$ and $Y$ respectively are,

The products $(A)$ and $(B)$ respectively are:

Product $A$ is

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