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(C) $1$. Identify the longest carbon chain containing both the double and triple bonds. The chain has $6$ carbons,so the parent name is hexen-yne.$2$.

Vedclass · Accepted Answer

$(2E)-2$-Bromohex$-2$-en$-4$-yne

Vedclass · Answer

(C) $1$. Identify the longest carbon chain containing both the double and triple bonds. The chain has $6$ carbons,so the parent name is hexen-yne.$2$. Numbering starts from the end that gives the lower locant to the multiple bonds. Numbering from the right gives the double bond at position $2$ and the triple bond at position $4$. Thus,it is hex$-2$-en$-4$-yne.$3$. At position $2$,there is a bromo group. So,$2$-bromohex$-2$-en$-4$-yne.$4$. Determine the configuration $(E/Z)$ at the double bond. Assign priorities using Cahn-Ingold-Prelog rules:- At $C-2$: $-Br$ (high priority) and $-CH_3$ (low priority).- At $C-3$: $-C\equiv C-CH_3$ (high priority) and $-H$ (low priority).- Since the high priority groups ($-Br$ and $-C\equiv C-CH_3$) are on opposite sides,the configuration is $E$.$5$. The correct name is $(2E)-2$-bromohex$-2$-en$-4$-yne.

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