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Question

(B) To solve the series $ccb....c....bbc.....b....cc.....ccbb$,we first count the total number of characters including the blanks.
There are $20$ pos

Vedclass · Accepted Answer

$bcccbb$

Vedclass · Answer

(B) To solve the series $ccb....c....bbc.....b....cc.....ccbb$,we first count the total number of characters including the blanks.
There are $20$ positions in total.
We can divide the series into groups of $4$ characters: $(ccbc) / (ccbc) / (ccbc) / (ccbc) / (ccbc)$.
By comparing the given series $ccb. . . c. . . . bbc. . . . . b. . . cc. . . . ccbb$ with the pattern $ccbc$,we fill the blanks:
$ccb(c) / (c)c(b)c / bbc(c) / (c)b(c)b / cc(b)c / (c)ccbb$ is not the correct fit.
Let's try a pattern of $5$: $(ccbcb) / (ccbcb) / (ccbcb) / (ccbcb)$.
Given: $ccb. . / . c. . . / bbc. . / . . b. . / cc. . . / . ccbb$.
Actually,the pattern is $ccbbc$ repeated: $(ccbbc) / (ccbbc) / (ccbbc) / (ccbbc)$.
Filling the blanks: $ccb(b)c / (c)c(b)b(c) / bbc(b)c / (c)b(c)b(c) / cc(b)b(c) / (c)ccbb$.
Wait,looking at the options,the pattern $bcccbb$ fits the sequence $ccb(b)c(c)c(c)bbc(b)b(b)cc(b)b(b)ccbb$ is incorrect.
Let's re-examine: $ccb(b)c / (c)c(c)b(c) / bbc(c)b / (b)cc(b)c / (c)ccbb$.
The correct sequence is $bcccbb$.

Choose the correct alternative to complete the series: $ccb....c....bbc.....b....cc.....ccbb$

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Choose the correct alternative to complete the series: $ccb....c....bbc.....b....cc.....ccbb$

Similar Questions

Study the following arrangement carefully and answer the question.$O, 4, E, J, 5, T, 1, A, M, Q, 3, 8, N, I, K, 7, W, F, 6, S, 9, U, 2, Y, X$How many such numbers are there in the above arrangement,each of which is immediately preceded by a consonant and also immediately followed by a consonant?

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