Chlorophyll present in green leaves of plants absorbs light at $4.620 \times 10^{14} \ Hz$. Calculate the wavelength of radiation in nanometer. Which part of the electromagnetic spectrum does it belong to?
(N/A) The wavelength $\lambda$ is calculated using the formula $\lambda = \frac{c}{\nu}$.
Given: $c = 3.0 \times 10^{8} \ m \ s^{-1}$ and $\nu = 4.620 \times 10^{14} \ Hz$.
$\lambda = \frac{3.0 \times 10^{8} \ m \ s^{-1}}{4.620 \times 10^{14} \ s^{-1}} = 0.6494 \times 10^{-6} \ m$.
Converting to nanometers: $0.6494 \times 10^{-6} \ m \times 10^{9} \ nm/m = 649.4 \ nm$.
Since the wavelength $649.4 \ nm$ falls within the range of $400 \ nm$ to $750 \ nm$,it belongs to the visible light region of the electromagnetic spectrum.
Given: $c = 3.0 \times 10^{8} \ m \ s^{-1}$ and $\nu = 4.620 \times 10^{14} \ Hz$.
$\lambda = \frac{3.0 \times 10^{8} \ m \ s^{-1}}{4.620 \times 10^{14} \ s^{-1}} = 0.6494 \times 10^{-6} \ m$.
Converting to nanometers: $0.6494 \times 10^{-6} \ m \times 10^{9} \ nm/m = 649.4 \ nm$.
Since the wavelength $649.4 \ nm$ falls within the range of $400 \ nm$ to $750 \ nm$,it belongs to the visible light region of the electromagnetic spectrum.
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