Chloro compound of vanadium has only spin mag | vedclass

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Question

The spin magnetic moment is given as,

$\mu =\sqrt{n(n+2)} $

$1.73 =\sqrt{n(n+2)} $

$n =1$

The configuration of vanadium when number of unp

Vedclass · Accepted Answer

$VCl _{4}$

Vedclass · Answer

The spin magnetic moment is given as,

$\mu =\sqrt{n(n+2)} $

$1.73 =\sqrt{n(n+2)} $

$n =1$

The configuration of vanadium when number of unpaired electron is $1$ is given as,

$V (23) =[ Ar ] 3 d^{3} 4 s^{2} $

$V ^{4+} =[ Ar ] 3 d^{1} 4 s^{0}$

Therefore, the chloride has the formula $VCl _{4}$

Chloro compound of vanadium has only spin magnetic moment of $1.73\, BM$. This vanadium chloride has the formula:

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