Certain quantity of water cools from 70,^oC t | vedclass

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Question

$\frac{	heta_{1}-	heta_{2}}{t}=K\left[\frac{	heta_{1}+	heta_{2}}{2}-	heta_{0}ight]$

$\frac{70-60}{10}=\mathrm{K}\left[\frac{70+60}{2}-	heta

Vedclass · Accepted Answer

$45$

Vedclass · Answer

$\frac{	heta_{1}-	heta_{2}}{t}=K\left[\frac{	heta_{1}+	heta_{2}}{2}-	heta_{0}ight]$

$\frac{70-60}{10}=\mathrm{K}\left[\frac{70+60}{2}-	heta_{0}ight] \ldots .(i)$

$\frac{60-54}{10}=\mathrm{K}\left[\frac{60+54}{2}-	heta_{0}ight]$  $...(ii)$

$\frac{10}{6}=\frac{65-	heta_{0}}{57-	heta_{0}}$

solving it $	heta_{0}=45^{\circ} \mathrm{C}$

Certain quantity of water cools from $70\,^oC$ to $60\,^oC$ in first $10\, minutes$ and to $54\,^oC$ in the next $10\, minutes$. The temperature of the surrounding is ......... $^oC$

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