A carbon resistor has a resistance specified | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The initial resistance $R_i$ is determined by the color code: Red $(2)$,Yellow $(4)$,Black $(10^0)$. Thus,$R_i = 24 	imes 10^0 = 24 \, \Omega$.Wh

Vedclass · Accepted Answer

White,Blue,Black

Vedclass · Answer

(A) The initial resistance $R_i$ is determined by the color code: Red $(2)$,Yellow $(4)$,Black $(10^0)$. Thus,$R_i = 24 	imes 10^0 = 24 \, \Omega$.When a wire is stretched to twice its length $(L_f = 2L_i)$,its cross-sectional area $A$ decreases such that $A_f = A_i / 2$ (since volume $V = AL$ is constant).The new resistance $R_f$ is given by $R_f = ho (L_f / A_f) = ho (2L_i / (A_i / 2)) = 4 ho (L_i / A_i) = 4 R_i$.Therefore,$R_f = 4 	imes 24 = 96 \, \Omega$.The new resistance $96 \, \Omega$ can be written as $9.6 	imes 10^1 \, \Omega$. However,standard color codes use integer values. Checking the options,$96 \, \Omega$ is closest to $96 	imes 10^0 \, \Omega$. The color code for $9$ is White,$6$ is Blue,and $10^0$ is Black. Thus,the new color code is White,Blue,Black.

$A$ carbon resistor has a resistance specified by three bands with colors red,yellow,and black. If the resistor is remolded to make a resistor twice its previous length,what will be the new color code?

Similar Questions

How are carbon film resistors prepared?

In the figure,a carbon resistor has bands of different colours on its body as shown. The value of the resistance is ................. $k\Omega$.

The resistance value of the given resistor is .......... $k\Omega$.

Give the sequence of colors of the rings marked on a resistor of $56 \, k\Omega$ with a tolerance of $\pm 5\%$.

The carbon resistor has three orange bands. The maximum value of resistance offered by the resistor will be . . . . . . .

Vedclass Test Series

Exam Paper Generator

Online Exam Module