A carbon resistor has a resistance specified | vedclass

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Question

(A) The initial resistance $R_i$ is determined by the color code: Red $(2)$,Yellow $(4)$,Black $(10^0)$.$R_i = 24 	imes 10^0 \, \Omega = 24 \, \Omega

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Brown,Red,Black

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(A) The initial resistance $R_i$ is determined by the color code: Red $(2)$,Yellow $(4)$,Black $(10^0)$.$R_i = 24 	imes 10^0 \, \Omega = 24 \, \Omega$.When the resistor is cut into two pieces of equal length,the resistance of each piece becomes half of the original resistance because $R = ho \frac{L}{A}$.$R_f = \frac{R_i}{2} = \frac{24}{2} = 12 \, \Omega$.The new resistance $12 \, \Omega$ can be written as $12 	imes 10^0 \, \Omega$.According to the color code table: $1$ is Brown,$2$ is Red,and $10^0$ is Black.Therefore,the new color code is Brown,Red,Black.

$A$ carbon resistor has a resistance specified by three bands with colors red,yellow,and black. If this resistor is cut into two pieces of equal length,what will be the new color code of each piece? (Neglect the tolerance of the $4^{th}$ band)

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