Carbon,silicon,and germanium have four valenc | vedclass

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Question

(A) The energy band gap $(E_{g})$ is the energy difference between the top of the valence band and the bottom of the conduction band.For elements in G

Vedclass · Accepted Answer

$(E_{g})_{C} > (E_{g})_{Si} > (E_{g})_{Ge}$

Vedclass · Answer

(A) The energy band gap $(E_{g})$ is the energy difference between the top of the valence band and the bottom of the conduction band.For elements in Group $14$ of the periodic table,as we move down the group,the atomic size increases and the strength of the covalent bonds decreases.Consequently,the energy required to excite an electron from the valence band to the conduction band decreases.The energy band gaps for these elements are approximately:Carbon (Diamond): $(E_{g}) \approx 5.4 \ eV$Silicon: $(E_{g}) \approx 1.1 \ eV$Germanium: $(E_{g}) \approx 0.7 \ eV$Therefore,the correct relationship is $(E_{g})_{C} > (E_{g})_{Si} > (E_{g})_{Ge}$.

List-$I$	List-$II$
$(A)$ Benzene	$1$. Phosgene
$(B)$ Ethylene	$2$. Silver mirror
$(C)$ Acetaldehyde	$3$. Mustard gas
$(D)$ Chloroform	$4$. $(4n + 2) \pi$ electrons
	$5$. Carbylamine

Carbon,silicon,and germanium have four valence electrons each. These are characterized by valence and conduction bands separated by energy band gaps equal to $(E_{g})_{C}$,$(E_{g})_{Si}$,and $(E_{g})_{Ge}$ respectively. Which of the following statements is true?

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Match the following lists:
List-$I$ List-$II$
$(A)$ Benzene $1$. Phosgene
$(B)$ Ethylene $2$. Silver mirror
$(C)$ Acetaldehyde $3$. Mustard gas
$(D)$ Chloroform $4$. $(4n + 2) \pi$ electrons
$5$. Carbylamine

The correct matching is:

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