Calculate the work required to be done to sto | vedclass

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Question

(A) Mass of the car $m = 1500 \, kg$.Velocity of the car $v = 60 \, km/h$.Convert velocity to $m/s$: $v = \frac{60 	imes 1000}{3600} = \frac{50}{3} \

Vedclass · Accepted Answer

$208333.3$

Vedclass · Answer

(A) Mass of the car $m = 1500 \, kg$.Velocity of the car $v = 60 \, km/h$.Convert velocity to $m/s$: $v = \frac{60 	imes 1000}{3600} = \frac{50}{3} \, m/s$.The kinetic energy $(KE)$ of the car is given by the formula $KE = \frac{1}{2} mv^2$.$KE = \frac{1}{2} 	imes 1500 	imes (\frac{50}{3})^2 \, J$.$KE = 750 	imes \frac{2500}{9} \, J$.$KE = 750 	imes 277.777... \, J = 208333.3 \, J$.According to the work-energy theorem, the work required to stop the car is equal to the change in its kinetic energy.Work done $= KE_{initial} - KE_{final} = 208333.3 \, J - 0 \, J = 208333.3 \, J$.Thus, the work required to stop the car is $208333.3 \, J$.

Calculate the work required to be done to stop a car of $1500 \, kg$ moving at a velocity of $60 \, km/h$. (in $J$)

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