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Question

(A) According to de Broglie's equation,$\lambda = \frac{h}{mv}$.Given:$h = 6.626 	imes 10^{-34} \,J s$$m = 9.109 	imes 10^{-31} \,kg$$v = 2.05 	ime

Vedclass · Accepted Answer

$3.548 	imes 10^{-11} \,m$

Vedclass · Answer

(A) According to de Broglie's equation,$\lambda = \frac{h}{mv}$.Given:$h = 6.626 	imes 10^{-34} \,J s$$m = 9.109 	imes 10^{-31} \,kg$$v = 2.05 	imes 10^{7} \,m s^{-1}$Substituting the values:$\lambda = \frac{6.626 	imes 10^{-34}}{(9.109 	imes 10^{-31})(2.05 	imes 10^{7})}$$\lambda = \frac{6.626 	imes 10^{-34}}{18.673 	imes 10^{-24}}$$\lambda = 0.3548 	imes 10^{-10} \,m = 3.548 	imes 10^{-11} \,m$.

Calculate the wavelength of an electron moving with a velocity of $2.05 \times 10^{7} \,m s^{-1}$.

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