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Question

(C) The relationship between wavelength $(\lambda)$ and wave number $(\bar{
u})$ is given by: $\lambda = \frac{1}{\bar{
u}}$Given $\bar{
u} = 11516

Vedclass · Accepted Answer

$868$

Vedclass · Answer

(C) The relationship between wavelength $(\lambda)$ and wave number $(\bar{
u})$ is given by: $\lambda = \frac{1}{\bar{
u}}$Given $\bar{
u} = 11516 \ cm^{-1}$.$\lambda = \frac{1}{11516 \ cm^{-1}} \approx 8.6835 	imes 10^{-5} \ cm$.To convert this to nanometers $(nm)$,we use the conversion factor $1 \ nm = 10^{-7} \ cm$:$\lambda = 8.6835 	imes 10^{-5} \ cm 	imes \frac{1 \ nm}{10^{-7} \ cm} = 868.35 \ nm \approx 868 \ nm$.

Calculate the wavelength for the emission of a photon having a wave number of $11516 \ cm^{-1}$. (in $nm$)

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