Calculate the volume of the unit cell for an element having a molar mass of $56 \ g \ mol^{-1}$ that forms $bcc$ unit cells. $\left[\rho \cdot N_{A} = 4.8 \times 10^{24} \ g \ cm^{-3} \ mol^{-1}\right]$
- A$1.17 \times 10^{-23} \ cm^3$
- B$4.79 \times 10^{-23} \ cm^3$
- C$3.31 \times 10^{-23} \ cm^3$
- D$2.33 \times 10^{-23} \ cm^3$
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