Calculate the volume of fcc unit cell in cm^3 | vedclass

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Question

(B) For an $fcc$ unit cell,the packing efficiency is $74\%$. This means the volume occupied by atoms is $0.74 	imes V_{cell}$. The void volume is the

Vedclass · Accepted Answer

$1.6 	imes 10^{-23}$

Vedclass · Answer

(B) For an $fcc$ unit cell,the packing efficiency is $74\%$. This means the volume occupied by atoms is $0.74 	imes V_{cell}$. The void volume is the remaining volume,which is $100\% - 74\% = 26\%$. Therefore,the void volume is $0.26 	imes V_{cell}$. Given that the void volume is $4.16 	imes 10^{-24} \ cm^3$,we have: $0.26 	imes V_{cell} = 4.16 	imes 10^{-24} \ cm^3$. $V_{cell} = \frac{4.16 	imes 10^{-24}}{0.26} \ cm^3$. $V_{cell} = 16 	imes 10^{-24} \ cm^3 = 1.6 	imes 10^{-23} \ cm^3$. Thus,the correct option is $B$.

Calculate the volume of $fcc$ unit cell in $cm^3$ if void volume of it is $4.16 \times 10^{-24} \ cm^3$.

Similar Questions

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