Calculate the uncertainty in the position of an electron $(mass = 9.1 \times 10^{-28} \ g)$ moving with a velocity of $3 \times 10^4 \ cm \ sec^{-1}$,if the uncertainty in velocity is $0.011 \%$ (in $cm$)?

$A$ microscope using suitable photons is employed to locate an electron in an atom within a distance of $0.1 \, \mathring{A}$. What is the uncertainty involved in the measurement of its velocity?

An electron is moving with a velocity of $600 \, m/s$ with an accuracy of $0.005\%$. The uncertainty in its position will be: ($h = 6.6 \times 10^{-34} \, kg \, m^2 \, s^{-1}$,mass of electron $m_e = 9.1 \times 10^{-31} \, kg$)

The equation $\Delta x \cdot \Delta p \ge \frac{h}{4\pi}$ shows

Provide the equation for a system where the energy of an atom or molecule does not change with time.

If a proton is accelerated to a velocity of $3 \times 10^7 \text{ ms}^{-1}$ which is accurate up to $\pm 0.5 \%$,then the uncertainty in its position will be $\ldots \ldots \ldots$ [mass of proton $= 1.66 \times 10^{-27} \text{ kg}$,$h = 6.6 \times 10^{-34} \text{ Js}$]