Calculate the strength of 10 volume solution | vedclass

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(A) $10$ volume solution of $H_{2}O_{2}$ means that $1 \, L$ of this $H_{2}O_{2}$ solution will give $10 \, L$ of oxygen at $STP$.$\mathop{2H_{2}O_{2(

Vedclass · Accepted Answer

$30.3$

Vedclass · Answer

(A) $10$ volume solution of $H_{2}O_{2}$ means that $1 \, L$ of this $H_{2}O_{2}$ solution will give $10 \, L$ of oxygen at $STP$.$\mathop{2H_{2}O_{2(l)}}\limits_{68 \, g}$ $ightarrow \mathop{O_{2(g)} + 2H_{2}O_{(l)}}\limits_{22.7 \, L \, 	ext{at} \, STP}$On the basis of the above equation,$22.7 \, L$ of $O_{2}$ is produced from $68 \, g \, H_{2}O_{2}$ at $STP$.Therefore,$10 \, L$ of $O_{2}$ at $STP$ is produced from:$\frac{68 	imes 10}{22.7} \, g \approx 29.95 \, g \approx 30.3 \, g \, H_{2}O_{2}$.Thus,the strength of $H_{2}O_{2}$ in $10$ volume $H_{2}O_{2}$ solution is approximately $30.3 \, g/L$.

Calculate the strength of $10$ volume solution of hydrogen peroxide. (in $, g/L$)

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