Calculate the solubility of gas in water at $1.2 \text{ atm}$ and $25^{\circ} C$ if Henry's law constant is $0.45 \text{ mol dm}^{-3} \text{ atm}^{-1}$ at $25^{\circ} C$.
- A$0.45 \text{ mol dm}^{-3}$
- B$0.54 \text{ mol dm}^{-3}$
- C$0.25 \text{ mol dm}^{-3}$
- D$0.31 \text{ mol dm}^{-3}$
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Henry's constant (in $kbar$) for four gases $\alpha, \beta, \gamma$ and $\delta$ in water at $298 \ K$ is given below:
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