Calculate the solubility of a gas in water at $260 \ mm \ Hg$ and $25^{\circ} C$ if Henry's law constant of the gas is $0.159 \ mol \ dm^{-3} \ atm^{-1}$ at $25^{\circ} C$.
- A$3.8 \times 10^{-2} \ mol \ dm^{-3}$
- B$5.4 \times 10^{-2} \ mol \ dm^{-3}$
- C$2.7 \times 10^{-2} \ mol \ dm^{-3}$
- D$1.2 \times 10^{-2} \ mol \ dm^{-3}$
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