Calculate the percentage hydrolysis of NaOCN | vedclass

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Question

(A) The salt $NaOCN$ is a salt of a strong base $(NaOH)$ and a weak acid $(HOCN)$.For such a salt,the degree of hydrolysis $h$ is given by the formula

Vedclass · Accepted Answer

$0.01$

Vedclass · Answer

(A) The salt $NaOCN$ is a salt of a strong base $(NaOH)$ and a weak acid $(HOCN)$.For such a salt,the degree of hydrolysis $h$ is given by the formula: $h = \sqrt{\frac{K_h}{C}} = \sqrt{\frac{K_w}{K_a 	imes C}}$.Given: $K_w = 10^{-14}$,$K_a = 3.33 	imes 10^{-4}$,and $C = 0.003 \ M = 3 	imes 10^{-3} \ M$.Substituting the values: $h = \sqrt{\frac{10^{-14}}{3.33 	imes 10^{-4} 	imes 3 	imes 10^{-3}}} = \sqrt{\frac{10^{-14}}{10^{-6}}} = \sqrt{10^{-8}} = 10^{-4}$.The percentage hydrolysis is $h 	imes 100 = 10^{-4} 	imes 100 = 0.01 \%$.

Calculate the percentage hydrolysis of $NaOCN$ in its $0.003 \ M$ aqueous solution ($K_a$ for $HOCN = 3.33 \times 10^{-4} \ M$) .....$\%$

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