Calculate the molarity of NaOH solution prepa | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Molarity $(M)$ is defined as the number of moles of solute per liter of solution.Step $1$: Calculate the number of moles of $NaOH$.Moles of $NaOH

Vedclass · Accepted Answer

$0.02$

Vedclass · Answer

(A) Molarity $(M)$ is defined as the number of moles of solute per liter of solution.Step $1$: Calculate the number of moles of $NaOH$.Moles of $NaOH = \frac{	ext{mass}}{	ext{molar mass}} = \frac{0.4 \ g}{40 \ g \ mol^{-1}} = 0.01 \ mol$.Step $2$: Convert the volume of the solution to liters.Volume $= 500 \ mL = 0.5 \ L$.Step $3$: Calculate Molarity.$M = \frac{	ext{moles of solute}}{	ext{volume of solution in liters}} = \frac{0.01 \ mol}{0.5 \ L} = 0.02 \ M$.

Calculate the molarity of $NaOH$ solution prepared by dissolving $0.4 \ g$ of $NaOH$ in enough water to form $500 \ mL$ of the solution. (in $M$)

Similar Questions

Calculate the mole fraction of benzene in a solution containing $30\%$ by mass in carbon tetrachloride.

Calculate the mass fraction and mass percentage of aspirin in a solution prepared by dissolving $3.65 \, g$ of aspirin in $25.08 \, g$ of water.

Calculate the molarity of a solution of ethanol in water in which the mole fraction of ethanol is $0.040$ (assume the density of water to be $1 \, g/mL$).

The $\% \ w/V$ unit is used in which branch of science?

What is the mole fraction of water in $10\%$ by weight $(w/w)$ of aqueous urea solution? [Given: Molar mass of $H, O, C$ and $N$ are $1, 16, 12$ and $14 \text{ g mol}^{-1}$ respectively.]

Vedclass Test Series

Exam Paper Generator

Online Exam Module