Calculate the force of gravitation between th | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) According to the universal law of gravitation,the force of attraction between the Earth and the Sun is given by:$F = \frac{G 	imes M_{	ext{Sun}}

Vedclass · Accepted Answer

$3.57 	imes 10^{22} \, N$

Vedclass · Answer

(C) According to the universal law of gravitation,the force of attraction between the Earth and the Sun is given by:$F = \frac{G 	imes M_{	ext{Sun}} 	imes M_{	ext{Earth}}}{R^2}$Where:$M_{	ext{Sun}} = 2 	imes 10^{30} \, kg$$M_{	ext{Earth}} = 6 	imes 10^{24} \, kg$$R = 1.5 	imes 10^{11} \, m$$G = 6.7 	imes 10^{-11} \, Nm^2 \, kg^{-2}$Substituting the values:$F = \frac{6.7 	imes 10^{-11} 	imes 2 	imes 10^{30} 	imes 6 	imes 10^{24}}{(1.5 	imes 10^{11})^2}$$F = \frac{80.4 	imes 10^{43}}{2.25 	imes 10^{22}}$$F = 35.73 	imes 10^{21} \, N = 3.57 	imes 10^{22} \, N$Thus,the gravitational force is $3.57 	imes 10^{22} \, N$.

Calculate the force of gravitation between the Earth and the Sun,given that the mass of the Earth $= 6 \times 10^{24} \, kg$ and of the Sun $= 2 \times 10^{30} \, kg$. The average distance between the two is $1.5 \times 10^{11} \, m$.

Similar Questions

In what direction does the buoyant force on an object immersed in a liquid act?

What do we call the gravitational force between the earth and an object?

Why is it difficult to hold a school bag having a strap made of a thin and strong string?

Amit buys a few grams of gold at the poles as per the instruction of one of his friends. He hands over the same when he meets him at the equator. Will the friend agree with the weight of gold bought? If not,why? [Hint: The value of $g$ is greater at the poles than at the equator.]

What is the acceleration of free fall?

Vedclass Test Series

Exam Paper Generator

Online Exam Module