Calculate the equivalent resistance in the combination shown in figure below
Calculate the equivalent resistance in the combination shown in figure below
Resistors $6$ ohm and $3$ ohm are in parallel Therefore, we have
$\frac{1}{ R _{ P }}=\frac{1}{ R _{1}}+\frac{1}{ R _{2}}$
Hence, $\frac{1}{ R _{ P }}=\frac{1}{3}+\frac{1}{6}=\frac{6+3}{6 \times 3}=\frac{9}{18}=\frac{1}{2}$
or $\quad R_{P}=2 \Omega$
Now, $2\, ohm$ and $R_{p}$ are in series
$\therefore$ $R = R _{1}+ R _{ P }=2+2=4 \Omega$
Therefore, the equivalent resistance of the 'circuit is $4\, ohm$.
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