Calculate the equilibrium concentration of $Pb^{2+}$ ions in a solution of $PbS$ containing $1 \times 10^{-11} \ mol \ dm^{-3}$ of sulphide ions. (Given $K_{sp}$ for $PbS = 8.0 \times 10^{-28}$)

  • A
    $8 \times 10^{-17} \ mol \ dm^{-3}$
  • B
    $4 \times 10^{-17} \ mol \ dm^{-3}$
  • C
    $8 \times 10^{-18} \ mol \ dm^{-3}$
  • D
    $8 \times 10^{-11} \ mol \ dm^{-3}$

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