Calculate the dispersive power for crown glas | vedclass

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Question

(C) The dispersive power $\omega$ is defined as the ratio of the angular dispersion to the mean deviation.It is given by the formula: $\omega = \frac{

Vedclass · Accepted Answer

$0.0164$

Vedclass · Answer

(C) The dispersive power $\omega$ is defined as the ratio of the angular dispersion to the mean deviation.It is given by the formula: $\omega = \frac{\mu_v - \mu_r}{\mu_y - 1}$,where $\mu_y \approx \frac{\mu_v + \mu_r}{2}$.Given: $\mu_v = 1.5230$ and $\mu_r = 1.5145$.First,calculate the mean refractive index: $\mu_y = \frac{1.5230 + 1.5145}{2} = \frac{3.0375}{2} = 1.51875$.Now,substitute the values into the formula: $\omega = \frac{1.5230 - 1.5145}{1.51875 - 1} = \frac{0.0085}{0.51875}$.Calculating the final value: $\omega \approx 0.016385$,which rounds to $0.0164$.

Calculate the dispersive power for crown glass from the given data if $\mu_v = 1.5230$ and $\mu_r = 1.5145$.

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