Calculate the amount of water (g) produced by | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The balanced chemical equation for the combustion of methane is:$CH_{4(g)} + 2O_{2(g)} \rightarrow CO_{2(g)} + 2H_2O_{(g)}$$(i)$ Calculate the mol

Vedclass · Accepted Answer

$36$

Vedclass · Answer

(B) The balanced chemical equation for the combustion of methane is:$CH_{4(g)} + 2O_{2(g)} ightarrow CO_{2(g)} + 2H_2O_{(g)}$$(i)$ Calculate the moles of methane $(CH_4)$:Molar mass of $CH_4 = 12 + (4 	imes 1) = 16 \ g/mol$.Moles of $CH_4 = \frac{16 \ g}{16 \ g/mol} = 1 \ mol$.$(ii)$ From the stoichiometry of the balanced equation:$1 \ mol$ of $CH_4$ produces $2 \ mol$ of $H_2O$.$(iii)$ Calculate the mass of water produced:Molar mass of $H_2O = (2 	imes 1) + 16 = 18 \ g/mol$.Mass of $H_2O = 2 \ mol 	imes 18 \ g/mol = 36 \ g$.

Calculate the amount of water $(g)$ produced by the combustion of $16 \ g$ of methane. (in $g$)

Similar Questions

The charge carried by $1 \text{ millimole}$ of $M^{n+}$ ions is $193 \text{ C}$. The value of $n$ is

$X \ g$ of benzoic acid on reaction with aqueous $NaHCO_3$ releases $CO_2$ that occupies $11.2 \ L$ volume at $STP$. The value of $X$ is . . . . . . $g$.

$100 \, mL$ of a given $H_2O_2$ sample in water (density $1.08 \, g/mL$) required $5 \, mL$ of $M/25 \, KMnO_4$ in acidic medium for its oxidation. Select the correct statement regarding $H_2O_2$ in the sample:

The moles of methane required to produce $81 \ g$ of water after complete combustion is $.... \times 10^{-2} \ mol.$ [nearest integer]

What is the mass of potassium chloride produced when $12.25 \ g$ of potassium chlorate undergoes decomposition (in $g$)? (Atomic masses: $K=39, Cl=35.5, O=16$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module