Calculate the amount of solute dissolved in 6 | vedclass

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(D) The relative lowering of vapour pressure is given by the formula: $\frac{\Delta P}{P_A^{\circ}} = x_B = \frac{n_B}{n_A + n_B}$.For dilute solution

Vedclass · Accepted Answer

$290.7$

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(D) The relative lowering of vapour pressure is given by the formula: $\frac{\Delta P}{P_A^{\circ}} = x_B = \frac{n_B}{n_A + n_B}$.For dilute solutions,$n_B \ll n_A$,so $\frac{\Delta P}{P_A^{\circ}} \approx \frac{n_B}{n_A} = \frac{W_B 	imes M_A}{M_B 	imes W_A}$.Given: $\frac{\Delta P}{P_A^{\circ}} = 0.025$,$W_A = 612 \ g$,$M_A = 18 \ g \ mol^{-1}$,$M_B = 342 \ g \ mol^{-1}$.Substituting the values: $0.025 = \frac{W_B 	imes 18}{342 	imes 612}$.$W_B = \frac{0.025 	imes 342 	imes 612}{18}$.$W_B = 0.025 	imes 342 	imes 34 = 290.7 \ g$.

Calculate the amount of solute dissolved in $612 \ g$ of water at $30^{\circ} C$ if molar mass of solute is $342 \ g \ mol^{-1}$ (Relative vapour pressure lowering is $0.025$ and molar mass of water $18 \ g \ mol^{-1}$ ). (in $g$)

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