Calculate solubility $(mol \ dm^{-3})$ of a sparingly soluble electrolyte $AB$ at $298 \ K$ if its solubility product is $1.6 \times 10^{-5}$?

What is the concentration of $Ba^{2+}$ when $BaF_2$ $(K_{sp} = 1.0 \times 10^{-6})$ begins to precipitate from a solution that is $0.30 \, M \ F^{-}$?

For a sparingly soluble,strong electrolyte salt,the following equilibrium is established in a saturated solution:
$AgIO_{3(s)} \rightleftharpoons Ag^+_{(aq)} + IO_{3(aq)}^-$
At a certain temperature,the solubility product of $AgIO_3$ is $K_{sp} = 1.0 \times 10^{-8}$. The molar mass of $AgIO_3$ is $283 \ g \ mol^{-1}$. What is the mass of $AgIO_3$ in $100 \ mL$ of its saturated solution?

$A$ precipitate is formed when:

$PbCl_2$ has a maximum concentration of $1.0 \times 10^{-3} \ M$ in its saturated aqueous solution at $25 \ ^oC$. Its solubility in a $0.1 \ M \ NaCl$ solution will be:

The solubility product of $Cr(OH)_3$ at $298 \ K$ is $6.0 \times 10^{-31}$. The concentration of hydroxide ions in a saturated solution of $Cr(OH)_3$ will be