Calculate the molarity and % W/V of 40 volum | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The relationship between volume strength and molarity $(M)$ is given by: $Volume \ strength = 11.2 	imes M$. Given volume strength = $40$. Theref

Vedclass · Accepted Answer

$3.57 \ M, 12.14\%$

Vedclass · Answer

(B) The relationship between volume strength and molarity $(M)$ is given by: $Volume \ strength = 11.2 	imes M$. Given volume strength = $40$. Therefore,$M = \frac{40}{11.2} \approx 3.57 \ M$. Now,$\% \ W/V = 	ext{Molarity} 	imes \frac{	ext{Molar mass of } H_2O_2}{10}$. Molar mass of $H_2O_2 = (2 	imes 1) + (2 	imes 16) = 34 \ g/mol$. $\% \ W/V = 3.57 	imes \frac{34}{10} = 3.57 	imes 3.4 = 12.138 \approx 12.14\%$. Thus,the molarity is $3.57 \ M$ and the $\% \ W/V$ is $12.14\%$.

$A$. Peroxide	$1$. $C_3O_2$
$B$. Superoxide	$2$. $PbO_2$
$C$. Dioxide	$3$. $KO_2$
$D$. Suboxide	$4$. $H_2O_2$

Calculate the molarity and $\% \ W/V$ of $40$ volume of $H_2O_2$ solution.

Similar Questions

When $H_{2}O_{2}$ is shaken with an acidified solution of $K_{2}Cr_{2}O_{7}$ in the presence of ether,the ethereal layer turns blue due to the formation of

$A$ commercial sample of $H_2O_2$ marked as $100$ volume hydrogen peroxide means:

$A$ commercial sample of hydrogen peroxide is labelled as $10$ volume. Its percentage strength is nearly ............... $\%$

Match List $I$ with List $II$ and select the correct answer using the codes given below the lists:
$A$. Peroxide $1$. $C_3O_2$
$B$. Superoxide $2$. $PbO_2$
$C$. Dioxide $3$. $KO_2$
$D$. Suboxide $4$. $H_2O_2$

The dihedral angles in gaseous and solid phases of $H_2O_2$ molecule respectively are

Vedclass Test Series

Exam Paper Generator

Online Exam Module