Calculate Delta H in kJ for the following rea | vedclass

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(A) To find the enthalpy change for the reaction $C_{(s)} + O_{2(g)} \longrightarrow CO_{2(g)}$,we use Hess's Law by adding the given equations:$(i) \

Vedclass · Accepted Answer

$-393$

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(A) To find the enthalpy change for the reaction $C_{(s)} + O_{2(g)} \longrightarrow CO_{2(g)}$,we use Hess's Law by adding the given equations:$(i) \ H_2O_{(g)} + C_{(s)} \longrightarrow CO_{(g)} + H_{2(g)} ; \Delta H_1 = +131 \ kJ$$(ii) \ CO_{(g)} + \frac{1}{2} O_{2(g)} \longrightarrow CO_{2(g)} ; \Delta H_2 = -282 \ kJ$$(iii) \ H_{2(g)} + \frac{1}{2} O_{2(g)} \longrightarrow H_2O_{(g)} ; \Delta H_3 = -242 \ kJ$Adding equations $(i)$,$(ii)$,and $(iii)$:$(H_2O_{(g)} + C_{(s)} + CO_{(g)} + \frac{1}{2} O_{2(g)} + H_{2(g)} + \frac{1}{2} O_{2(g)})$ $\longrightarrow (CO_{(g)} + H_{2(g)} + CO_{2(g)} + H_2O_{(g)})$Canceling common species on both sides,we get:$C_{(s)} + O_{2(g)} \longrightarrow CO_{2(g)}$The total enthalpy change is $\Delta H = \Delta H_1 + \Delta H_2 + \Delta H_3 = 131 + (-282) + (-242) = -393 \ kJ$.

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