Calculate $[H^{+}]$ of $0.2 \ M$ $HCN$ in $1 \ M$ $KCN$ solution. Given $K_{a(HCN)} = 4 \times 10^{-10}$.

  • A
    $8 \times 10^{-11} \ M$
  • B
    $4 \times 10^{-10} \ M$
  • C
    $2 \times 10^{-10} \ M$
  • D
    $1 \times 10^{-10} \ M$

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