Calculate the pH of a 0.37 g Ca(OH)_2 soluti | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $1$. Calculate the molar mass of $Ca(OH)_2$: $40 + 2 	imes (16 + 1) = 40 + 34 = 74 \ g/mol$. $2$. Calculate the number of moles of $Ca(OH)_2$: $n

Vedclass · Accepted Answer

$12.6$

Vedclass · Answer

(A) $1$. Calculate the molar mass of $Ca(OH)_2$: $40 + 2 	imes (16 + 1) = 40 + 34 = 74 \ g/mol$. $2$. Calculate the number of moles of $Ca(OH)_2$: $n = \frac{0.37 \ g}{74 \ g/mol} = 0.005 \ mol$. $3$. Calculate the molarity of $Ca(OH)_2$: $M = \frac{0.005 \ mol}{0.2 \ L} = 0.025 \ M$. $4$. Since $Ca(OH)_2$ is a strong base,it dissociates as $Ca(OH)_2 ightarrow Ca^{2+} + 2OH^-$. $5$. The concentration of $OH^-$ ions is $[OH^-] = 2 	imes 0.025 \ M = 0.05 \ M$. $6$. Calculate $pOH$: $pOH = -\log[OH^-] = -\log(0.05) = -\log(5 	imes 10^{-2}) = 2 - \log(5) \approx 2 - 0.699 = 1.301$. $7$. Calculate $pH$: $pH = 14 - pOH = 14 - 1.301 = 12.699 \approx 12.7$.

Calculate the $pH$ of a $0.37 \ g$ $Ca(OH)_2$ solution in $200 \ mL$ of water. (Atomic masses: $Ca = 40, O = 16, H = 1$)

Similar Questions

The $pH$ of a $0.001 \, N \, KOH$ solution is .....

Which of the following solutions has the highest $pH$?

What is the $pH$ of $1 \times 10^{-4} \ M \ H_2SO_4$ solution?

What is the normality of an aqueous solution of $H_2SO_4$ having $pH = 1$ (in $N$)?

Calculate the $pH$ of $0.0035 \ M \ Ba(OH)_2$ solution.

Vedclass Test Series

Exam Paper Generator

Online Exam Module